python - connecting ICE nodes

[milanvasek]

Hi.
I'm sorry for probably some basic question but my knowledge of python is very limited (well i have no idea...)

Here is the image:



and here is my problem:

I create a node (modify shape) with simple python command and I want to plug it into ScatterHub node, "modify" port. But right know it just replaces the connection that is already there. Is there a simple way to find if the port is already connected and if it is, create a new port and connect node there (or if second one is already connected too, create third one etc...)
I was trying to look into ICEflowBuilder, but its just too confusing for me because it uses JS or VB and there is a lot of stuff

Please, I would really appreciate any help.

[EricTRocks]

If you can get to the node via scripting the following code may help

Code: Select all

xsi = Application
log = xsi.LogMessage
collSel = xsi.Selection

collPorts = collSel(0).InputPorts
dValuePorts = {}
lValuePorts = [x for x in collPorts if x.Name.startswith("value")]

for eachValPort in lValuePorts:
	dValuePorts[eachValPort.Name] = eachValPort.IsConnected

log(dValuePorts)

you'll want to change the section that says ".startswith()" to whatever the port name you're looking for starts with. So probably ".startswith("modify")

[milanvasek]

i can't say i really understand it now, but thanks a lot. i'll try it in the evening when i get back to softimage

[EricTRocks]

well it simply demonstrates how you can get the InputPorts of a node and also get whether it is connected or not. Not sure how proficient you are with Python or not but what I did was basically get all the InputPorts whose name starts with "value". Then I add them to a Python dictionary where the port name is the key and true or false depending on whether the port is connected or not. From there you can build logic to create a new port or connect to an open one.